A parallel plate capacitor of capacitance $20 \mu$F$$ is being charged by a voltage source whose potential is changing at the rate of $3$ V/s$.$ The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively:

The ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic wave is: $(c =$speed of electromagnetic waves$)$

For a plane electromagnetic wave propagating in the x-direction, which one of the following combinations gives the correct possible directions for the electric field ($E$) and magnetic field ($B$) respectively?

When light propagates through a material medium of relative permittivity $\varepsilon_r$ and relative permeability $\mu_r,$ the velocity of light, $v$ is given by (where $c$ is the velocity of light in vacuum):

Match List - I with List - II regarding electromagnetic waves and their wavelengths:

In a plane electromagnetic wave traveling in free space, the electric field component oscillates sinusoidally at a frequency of $2.0 \times 10^{10} Hz$ and amplitude 48 V/m. Then the amplitude of oscillating magnetic field is: (Speed of light in free space $= 3 \times 10^{8} m/s)$

A parallel plate capacitor is charged by connecting it to a battery through a resistor. If I is the current in the circuit, then in the gap between the plates:

The property which is NOT of an electromagnetic wave travelling in free space is that: