Kelvi

In a plane electromagnetic wave traveling in free space, the electric field component oscillates sinusoidally at a frequency of $2.0 \times 10^{10} Hz$ and amplitude 48 V/m. Then the amplitude of oscillating magnetic field is: (Speed of light in free space $= 3 \times 10^{8} m/s)$

medium

Electromagnetic Waves

2023

physics

$1.6 \times 10^{-9} T$

$1.6 \times 10^{-8} T$

Explanation

To find the amplitude of the oscillating magnetic field in a plane electromagnetic wave, we use the relationship between the electric field $(E)$ and the magnetic field $(B)$ in free space. $\\ \\$ The relationship is given by: $\\ E = c \cdot B \\ \\$

Our AI powered practice platform can help you achieve your doctor dream.

Practice 2000+ previous year NEET questions
More practice, more score
AI generated hints
Use hints to get start solving
AI companion chat to clear doubts 24*7
Ask any question, get instant answers
AI generated solutions
Get detailed step by step solutions
Check related NCERT content
Read while solving
Track your progress
Improve every day