A beam of light of $\lambda = 600$ nm from a distant source falls on a single slit $1$ mm wide and the resulting diffraction pattern is observed on a screen $2$ m away. The distance between first dark fringes on either side of the central bright fringe is

In the Young’s double slit experiment, the intensity of light at a point on the screen where the path difference is $\lambda$ is $K$ ($\lambda$ being the wavelength of light used). The intensity at a point where the path difference is $\lambda/4$ will be

In a double-slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 nm is used. What will be the width of each slit for obtaining 10 maxima of double slit within the central maxima of single slit pattern?

For a parallel beam of monochromatic light of wavelength $\lambda,$ diffraction is produced by a single slit whose width $a$ is of the order of the wavelength of the light. If $D$ is the distance of the screen from the slit, the width of the central maxima will be

The intensity of the maximum in a Young’s double-slit experiment is I₀. Distance between two slits is d = 5λ, where λ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance D = 10d?

In a diffraction pattern due to a single slit of width a, the first minimum is observed at an angle 30° when light of wavelength 5000 Å is incident on the slit. The first secondary maximum is observed at an angle of

Two polaroids $P_1$ and $P_2$ are placed with their axis perpendicular to each other. Unpolarized light $I_0$ is incident on $P_1.$ A third polaroid $P_3$ is kept in between $P_1$ and $P_2$ such that its axis makes an angle $45°$ with that of $P_1.$ The intensity of transmitted light through $P_2$ is

In Young’s double slit experiment, the separation $d$ between the slits is $2$ mm, the wavelength $\lambda$ of the light used is $5896$ Å and distance $D$ between the screen and slits is $100$ cm. It is found that the angular width of the fringes is $0.20^{\circ}.$ To increase the fringe angular width to $0.21^{\circ}$ (with same $\lambda$ and $D),$ the separation between the slits needs to be changed to

Pick the wrong answer in the context of rainbow formation.

In a double slit experiment, when light of wavelength $400$ nm was used, the angular width of the first minima formed on a screen placed $1$ m away, was found to be $0.2^\circ.$ What will be the angular width of the first minima, if the entire experimental apparatus is immersed in water? $\mu_{water} = \frac{4}{3}$

In Young’s double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes:

In a Young's double slit experiment, a student observes $8$ fringes in a certain segment of screen when a monochromatic light of $600$ nm wavelength is used. If the wavelength of light is changed to $400$ nm, then the number of fringes he would observe in the same region of the screen is:

For Young's double slit experiment, two statements are given below:$\newline$Statement I: If the screen is moved away from the plane of slits, angular separation of the fringes remains constant.$\newline$Statement II: If the monochromatic source is replaced by another monochromatic source of larger wavelength, the angular separation of fringes decreases.$\newline$In the light of the above statements, choose the correct answer from the options given below:

If the monochromatic source in Young’s double slit experiment is replaced by white light, then:

An unpolarised light beam strikes a glass surface at Brewster’s angle. Then: