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An iron rod of susceptibility $599$ is subjected to a magnetizing field of $1200$ A/m. The permeability of the material of the rod is: $\quad (\mu_0 = 4\pi \times 10^{-7}$ Tm/A $)$

easy

Magnetism and Matter

2020

physics

$8.0 \times 10^{-5}$ Tm/A

$2.4\pi \times 10^{-5}$ Tm/A

Explanation

To solve this problem, we need to find the permeability of the material of the rod. $\\$ Given: $\\$ • Magnetic susceptibility $\chi_m = 599 \\$ • Magnetizing field $H = 1200 \, \mathrm{A/m} \\$

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An iron rod of susceptibility 599 599 599 is subjected to a magnetizing field of 1200 1200 1200 A/m. The permeability of the material of the rod is:(μ0=4π×10−7 \quad (\mu_0 = 4\pi \times 10^{-7} (μ0​=4π×10−7 Tm/A)))

Explanation

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An iron rod of susceptibility $599$ is subjected to a magnetizing field of $1200$ A/m. The permeability of the material of the rod is: $\quad (\mu_0 = 4\pi \times 10^{-7}$ Tm/A $)$