Kelvi

The number of photons per second on an average emitted by the source of monochromatic light of wavelength $600$ nm, when it delivers the power of $3.3 \times 10^{-3}$ watt will be: $\newline (h=6.6 \times 10^{-34}$ Js $)$

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Dual Nature of Radiation and Matter

2021

physics

$10^{18}$

$10^{17}$

$10^{16}$

Explanation

To solve this problem, we need to find the number of photons emitted per second by a source of monochromatic light. $\\$ Given: $\\$ • Wavelength $\lambda = 600$ nm $= 600 \times 10^{-9}$

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The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 600 600 nm, when it delivers the power of 3.3×10−3 3.3 \times 10^{-3} 3.3×10−3 watt will be:(h=6.6×10−34 \newline (h=6.6 \times 10^{-34} (h=6.6×10−34 Js)))

Explanation

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The number of photons per second on an average emitted by the source of monochromatic light of wavelength $600$ nm, when it delivers the power of $3.3 \times 10^{-3}$ watt will be: $\newline (h=6.6 \times 10^{-34}$ Js $)$