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The number of sigma ( σ \sigma σ ) and pi ( π \pi π ) bonds in pent-2-en-4-yne is:
easy
Organic Chemistry Some Basic Principles and Techniques
2019
chemistry
10 σ 10\sigma 10 σ bonds and 3 π 3\pi 3 π bonds
8 σ 8\sigma 8 σ bonds and 5 π 5\pi 5 π bonds
11 σ 11\sigma 11 σ bonds and 2 π 2\pi 2 π bonds
13 σ 13\sigma 13 σ bonds and no π \pi π bonds
Explanation To determine the number of sigma ( σ \sigma σ ) and pi ( π \pi π ) bonds in pent-2-en-4-yne, we first need to understand its structure. \\
Pent-2-en-4-yne is an organic compound with the following structure: \\
CH 3 − _3- 3 −
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CH
CH
C
CH
Let's analyze the structure step-by-step:
1. The compound has a total of 5 carbon atoms.
2. The suffix "-ene" indicates a double bond, and "-yne" indicates a triple bond.
3. The position numbers (2-en, 4-yne) indicate the location of the double and triple bonds.
Now, let's count the bonds:
• Between
C
and
C
a single
bond.
• Between
C
and
C
one
bond and one
bond (double bond).
• Between
C
and
C
a single
bond.
• Between
C
and
C
one
bond and two
bonds (triple bond).
Additionally, each carbon atom forms bonds with hydrogen atoms to satisfy the tetravalency of carbon:
•
C
is bonded to 3 hydrogen atoms (3
bonds).
•
C
is bonded to 1 hydrogen atom (1
bond).
•
C
is bonded to 1 hydrogen atom (1
bond).
•
C
has no hydrogen atoms bonded (0
bonds).
•
C
is bonded to 1 hydrogen atom (1
bond).
Now, let's count the total number of
and
bonds:
Total
bonds:
• 4
bonds between carbon atoms.
• 6
bonds with hydrogen atoms.
Total
bonds
= 4 + 6 = 10 = 4 + 6 = 10 \\
= 4 + 6 = 10 Total
bonds:
• 1
bond in the double bond.
• 2
bonds in the triple bond.
Total
bonds
= 1 + 2 = 3 = 1 + 2 = 3 \\
= 1 + 2 = 3 Therefore, the number of
bonds is 10 and the number of
bonds is 3.
This corresponds to Option 1: 10
bonds and 3
bonds.