Kelvi

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20$ m/s $^2$ at a distance of $5$ m from the mean position. The time period of oscillation is

medium

Oscillations

2018

physics

$2$ s

$\pi$ s

$2\pi$ s

$1$ s

Explanation

To solve this problem, we need to use the formula for the acceleration of a simple harmonic oscillator. $\\$ The acceleration $a$ of a simple harmonic oscillator is given by: $\\ a = -\omega^2 x \\$ where $\omega$

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A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 20 20 m/s2^2 2 at a distance of 5 5 5 m from the mean position. The time period of oscillation is

Explanation

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A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20$ m/s $^2$ at a distance of $5$ m from the mean position. The time period of oscillation is