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Match List I with List II. Column I Column II A. [Co(NH₃)₅(NO₂)]Cl₂ I. Solvate isomerism B. [Co(NH₃)₅(SO₄)]Br II. Linkage isomerism C. [Co(NH₃)₆][Cr(CN)₆] III. Ionization isomerism D. [Cr(H₂O)₆]Cl₃ IV. Coordination isomerism
hard
Coordination Compounds
2024
chemistry
Explanation To solve this problem, we need to match the given complexes in List I with the types of isomerism in List II.
\newline Let's analyze each complex:
\newline
\newline A. [ C o ( N H 3 ) 5 ( N O 2 ) ] C l 2 : [Co(NH_3)_5(NO_2)]Cl_2:
\newline [ C o ( N H 3 ​ ) 5 ​ ( N O 2 ​ )] C l 2 ​ :
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• This complex can exhibit linkage isomerism. The ligand NO
can bind through the nitrogen atom (nitro) or the oxygen atom (nitrito).
• Therefore, A matches with II (Linkage isomerism).
B.
[ C o ( N H 3 ) 5 ( S O 4 ) ] B r : [Co(NH_3)_5(SO_4)]Br:
\newline [ C o ( N H 3 ​ ) 5 ​ ( S O 4 ​ )] B r : • This complex can exhibit ionization isomerism. The sulfate (SO
) can be inside the coordination sphere, or it can be outside, swapping places with the bromide ion (Br
).
• Therefore, B matches with III (Ionization isomerism).
C.
[ C o ( N H 3 ) 6 ] [ C r ( C N ) 6 ] : [Co(NH_3)_6][Cr(CN)_6]:
\newline [ C o ( N H 3 ​ ) 6 ​ ] [ C r ( CN ) 6 ​ ] : • This complex can exhibit coordination isomerism. The cobalt and chromium can exchange their ligands, leading to different coordination entities.
• Therefore, C matches with IV (Coordination isomerism).
D.
[ C r ( H 2 O ) 6 ] C l 3 : [Cr(H_2O)_6]Cl_3:
\newline [ C r ( H 2 ​ O ) 6 ​ ] C l 3 ​ : • This complex can exhibit solvate isomerism, where the water molecules can be part of the coordination sphere or outside it.
• Therefore, D matches with I (Solvate isomerism).
Thus, the correct matching is:
A->II, B->III, C->IV, D->I
This corresponds to Option 3.