Kelvi

The number of possible natural oscillations of an air column in a pipe closed at one end of length $85$ cm whose frequencies lie below $1250$ Hz are (velocity of sound $= 340$ m/s)

medium

Waves

2014

physics

Explanation

To solve this problem, we need to determine the number of natural oscillations (harmonics) of an air column in a pipe closed at one end. $\\$ The fundamental frequency and its harmonics for a pipe closed at one end are given by: $\\ f_n = \frac{(2n-1) \cdot v}{4L} \\$

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The number of possible natural oscillations of an air column in a pipe closed at one end of length 85 85 85 cm whose frequencies lie below 1250 1250 1250 Hz are (velocity of sound =340 = 340 =340 m/s)

Explanation

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The number of possible natural oscillations of an air column in a pipe closed at one end of length $85$ cm whose frequencies lie below $1250$ Hz are (velocity of sound $= 340$ m/s)