To solve this problem, we need to determine during which phase(s) of the cell cycle the amount of DNA in a cell remains at the 4C level, given that the initial amount is 2C.$\newline$Let's analyze the cell cycle phases:$\newline \bullet$G₀ and G₁ Phases:$\newline$ - In the G₀ phase, cells are in a quiescent state and do not actively divide. The DNA content remains at 2C.$\newline$ - In the G₁ phase, cells prepare for DNA replication, but the DNA content remains at 2C until the S phase begins.$\newline \bullet$S Phase:$\newline$ - During the S phase, DNA replication occurs, doubling the DNA content from 2C to 4C.$\newline \bullet$G₂ Phase:$\newline$ - After the S phase, the cell enters the G₂ phase, where the DNA content remains at 4C as the cell prepares for mitosis.$\newline \bullet$M Phase (Mitosis):$\newline$ - During mitosis, the DNA content remains at 4C until the cell divides, resulting in two daughter cells each with 2C DNA content.$\newline$Based on this analysis, the DNA content remains at 4C during the G₂ and M phases.$\newline$Therefore, the correct option is Option 4: G₂ and M.