Kelvi

A solid cylinder of mass $2$ kg and radius $4$ cm is rotating about its axis at the rate of $3$ rpm. The torque required to stop it after $2\pi$ revolutions is:

hard

System of Particles and Rotational Motion

2019

physics

$2 \times 10^{-6}$ N m

$2 \times 10^{-3}$ N m

$12 \times 10^{-4}$

Explanation

To solve this problem, we need to calculate the torque required to stop a rotating solid cylinder. $\\$ Given: $\\$ • Mass of the cylinder $m = 2$ kg $\\$ • Radius of the cylinder $R = 4$ cm $= 0.04$

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A solid cylinder of mass 2 2 2 kg and radius 4 4 4 cm is rotating about its axis at the rate of 3 3 3 rpm. The torque required to stop it after 2π 2\pi 2π revolutions is:

Explanation

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A solid cylinder of mass $2$ kg and radius $4$ cm is rotating about its axis at the rate of $3$ rpm. The torque required to stop it after $2\pi$ revolutions is: