Kelvi

The resistance in the two arms of the meter bridge are $5 \Omega$ and $R \Omega$ , respectively. When the resistance $R$ is shunted with an equal resistance, the new balance point is at $1.6 l_1.$ The resistance $R$ is

hard

Current Electricity

2014

physics

$10 \Omega$

$15 \Omega$

$20 \Omega$

$25 \Omega$

Explanation

To solve this problem, we will use the principle of the meter bridge (Wheatstone bridge). $\\$ Initially, the balance condition is given by: $\\ \frac{5}{R} = \frac{l_1}{100 - l_1} \\$

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The resistance in the two arms of the meter bridge are 5Ω 5 \Omega 5Ω and RΩ R \Omega RΩ, respectively. When the resistance R R R is shunted with an equal resistance, the new balance point is at 1.6l1. 1.6 l_1. 1.6l1​. The resistance R R R is

Explanation

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The resistance in the two arms of the meter bridge are $5 \Omega$ and $R \Omega$ , respectively. When the resistance $R$ is shunted with an equal resistance, the new balance point is at $1.6 l_1.$ The resistance $R$ is