To solve this problem, we need to match the floral formulas in Column-I with the correct families in Column-II.$\newline$Let's analyze each option:$\newline\newline$(a) $\%\ \odot \ K_{(5)} \ C_{1+2+(2)} \ A_{(9)+1} \ G_{1} \newline$• This floral formula represents the family Fabaceae.$\newline$• Characteristics: Papilionaceous corolla, diadelphous stamens, monocarpellary ovary.$\newline\newline$(b) $\odot \ \oplus \ K_{(5)} \ C_{(5)} \ A_{5} \ G_{2} \newline$• This floral formula represents the family Solanaceae.$\newline$• Characteristics: Actinomorphic, pentamerous, bicarpellary ovary.$\newline\newline$(c) $\odot \ \oplus \ P_{(3+3)} \ A_{3+3} \ G_{(3)} \newline$• This floral formula represents the family Liliaceae.$\newline$• Characteristics: Trimerous flowers, superior ovary, monocot family.$\newline\newline$(d) $\odot \ \oplus \ K_{2+2} \ C_{4} \ A_{2-4} \ G_{(2)} \newline$• This floral formula represents the family Brassicaceae.$\newline$• Characteristics: Tetradynamous stamens, bicarpellary ovary, cruciform corolla.$\newline\newline$Matching the columns:$\newline$(a) matches with (iii) Fabaceae$\newline$(b) matches with (iv) Solanaceae$\newline$(c) matches with (ii) Liliaceae$\newline$(d) matches with (i) Brassicaceae$\newline\newline$Therefore, the correct option is Option 1:$\newline$(a)->(iii), (b)->(iv), (c)->(ii), (d)->(i)