Kelvi

The mean free path for a gas, with molecular diameter $d$ and number density $n$ can be expressed as:

easy

Kinetic Theory

2020

physics

$\frac{1}{\sqrt{2} n \pi d^2}$

$\frac{1}{\sqrt{2} n^2 \pi d^2}$

$\frac{1}{\sqrt{2} n^2 {\pi}^2 d^2}$

$\frac{1}{\sqrt{2} n \pi d}$

Explanation

To solve this problem, we need to understand the concept of mean free path in a gas. $\\$ The mean free path $(\lambda)$ is the average distance a molecule travels between collisions. $\\$ It is given by the formula: $\\ \lambda = \frac{1}{\sqrt{2} n \pi d^2} \\$

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The mean free path for a gas, with molecular diameter d d d and number density n n n can be expressed as:

Explanation

Our AI powered practice platform can help you achieve your doctor dream.

The mean free path for a gas, with molecular diameter $d$ and number density $n$ can be expressed as: