Kelvi

A radio isotope $X$ with a half-life $1.4 \times 10^9$ years decays to $Y$ which is stable. A sample of the rock from a cave was found to contain $X$ and $Y$ in the ratio $1:7.$ The age of the rock is

medium

Nuclei

2014

physics

$1.96 \times 10^9$ years

$3.92 \times 10^9$ years

$4.20 \times 10^9$

Explanation

To solve this problem, we will use the concept of radioactive decay and the formula for half-life. $\\$ Given: $\\$ • Half-life of isotope $X = 1.4 \times 10^9$ years $\\$ • Ratio of $X$

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A radio isotope X X X with a half-life 1.4×109 1.4 \times 10^9 1.4×109 years decays to Y Y Y which is stable. A sample of the rock from a cave was found to contain X X X and Y Y Y in the ratio 1:7. 1:7. 1:7. The age of the rock is

Explanation

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A radio isotope $X$ with a half-life $1.4 \times 10^9$ years decays to $Y$ which is stable. A sample of the rock from a cave was found to contain $X$ and $Y$ in the ratio $1:7.$ The age of the rock is