Kelvi

The electric field in a certain region is acting radially outward and is given by $E = A r.$ A charge contained in a sphere of radius $a$ centred at the origin of the field, will be given by

medium

Electric Charges and Fields

2015

physics

$A \varepsilon_0 a^2$

$4\pi \varepsilon_0 A a^3$

$\varepsilon_0 A a^3$

$4\pi \varepsilon_0 A a^2$

Explanation

To solve this problem, we will use Gauss's Law, which relates the electric field to the charge enclosed by a Gaussian surface. $\\$ Gauss's Law is given by: $\\ \oint E \cdot dA = \frac{Q_{enc}}{\varepsilon_0} \\$

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The electric field in a certain region is acting radially outward and is given by E=Ar. E = A r. E=Ar. A charge contained in a sphere of radius a a a centred at the origin of the field, will be given by

Explanation

Our AI powered practice platform can help you achieve your doctor dream.

The electric field in a certain region is acting radially outward and is given by $E = A r.$ A charge contained in a sphere of radius $a$ centred at the origin of the field, will be given by