Kelvi

A charged particle having drift velocity of $7.5 \times 10^{-4}$ m/s in an electric field of $3 \times 10^{-10}$ V/m, has a mobility in m $^2$ V $^{-1}$ s $^{-1}$ of:

easy

Current Electricity

2020

physics

$2.5 \times 10^6$

$2.5 \times 10^{-6}$

$2.25 \times 10^{-15}$

Explanation

To solve this problem, we need to find the mobility of a charged particle. $\\$ Mobility $(\mu)$ is defined as the drift velocity per unit electric field. $\\$ The formula for mobility is: $\\ \mu = \frac{v_d}{E} \\$

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A charged particle having drift velocity of 7.5×10−4 7.5 \times 10^{-4} 7.5×10−4 m/s in an electric field of 3×10−10 3 \times 10^{-10} 3×10−10 V/m, has a mobility in m2^2 2 V−1^{-1} −1 s−1^{-1} −1 of:

Explanation

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A charged particle having drift velocity of $7.5 \times 10^{-4}$ m/s in an electric field of $3 \times 10^{-10}$ V/m, has a mobility in m $^2$ V $^{-1}$ s $^{-1}$ of: