Kelvi

A square loop ABCD carrying a current $i$ is placed near and coplanar with a long straight conductor XY carrying a current $I,$ the net force on the loop will be

hard

Moving Charges and Magnetism

2016

physics

$\frac{2 \mu_0 IiL}{3 \pi}$

$\frac{\mu_0 IiL}{2 \pi}$

$\frac{2 \mu_0 Ii}{3 \pi L}$

$\frac{\mu_0 Ii}{2 \pi L}$

Explanation

To solve this problem, we need to calculate the net force on the square loop ABCD due to the long straight conductor XY. $\\$ The force between two parallel current-carrying conductors is given by: $\\ F = \frac{\mu_0}{2\pi} \cdot \frac{I_1 I_2}{d} \cdot L \\$

Our AI powered practice platform can help you achieve your doctor dream.

Practice 2000+ previous year NEET questions
More practice, more score
AI generated hints
Use hints to get start solving
AI companion chat to clear doubts 24*7
Ask any question, get instant answers
AI generated solutions
Get detailed step by step solutions
Check related NCERT content
Read while solving
Track your progress
Improve every day

A square loop ABCD carrying a current i i i is placed near and coplanar with a long straight conductor XY carrying a current I, I, I, the net force on the loop will be

Explanation

Our AI powered practice platform can help you achieve your doctor dream.

A square loop ABCD carrying a current $i$ is placed near and coplanar with a long straight conductor XY carrying a current $I,$ the net force on the loop will be