Kelvi

A force $F = 20 + 10y$ acts on a particle in the y-direction where $F$ is in newton and $y$ in meter. Work done by this force to move the particle from $y = 0$ to $y = 1$ m is:

medium

Work, Energy and Power

2019

physics

$30$ J

$5$ J

$25$ J

$20$ J

Explanation

To solve this problem, we need to calculate the work done by the force $F$ as the particle moves from $y = 0$ to $y = 1$ m. $\\$ The force acting on the particle is given by: $\\ F = 20 + 10y \\$

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A force F=20+10y F = 20 + 10y F=20+10y acts on a particle in the y-direction where F F F is in newton and y y y in meter. Work done by this force to move the particle from y=0 y = 0 y=0 to y=1 y = 1 y=1 m is:

Explanation

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A force $F = 20 + 10y$ acts on a particle in the y-direction where $F$ is in newton and $y$ in meter. Work done by this force to move the particle from $y = 0$ to $y = 1$ m is: