To solve this problem, we need to understand the electrolytic reduction of nitrobenzene in a strongly acidic medium.$\newline$When nitrobenzene is subjected to electrolytic reduction in an acidic medium, it undergoes a series of reduction steps.$\newline$The reduction process involves the following steps:$\newline$1. Nitrobenzene $(C_6H_5NO_2)$ is first reduced to nitrosobenzene $(C_6H_5NO). \newline$2. Nitrosobenzene is further reduced to phenylhydroxylamine $(C_6H_5NHOH). \newline$3. In a strongly acidic medium, phenylhydroxylamine undergoes a rearrangement to form $p$-aminophenol $(C_6H_4(NH_2)OH). \newline$The overall reaction can be summarized as follows:$\newline C_6H_5NO_2 \xrightarrow{\ electrolytic \ reduction, \ acidic \ medium} C_6H_4(NH_2)OH \newline$Analyzing the options:$\newline$• Option 1: Azoxybenzene is not formed in this process.$\newline$• Option 2: Azobenzene is not formed in this process.$\newline$• Option 3: Aniline is not the product of this specific reaction.$\newline$• Option 4: $p$-Aminophenol is the correct product of the electrolytic reduction of nitrobenzene in a strongly acidic medium.$\newline$Therefore, the correct option is Option 4.