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Which one of the following elements is unable to form MF63āā ion?
medium
The d and f Block Elements
2018
chemistry
Explanation
To solve this problem, we need to determine which element cannot form the MF63āā ion.The formation of MF63āā
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Sign up / Login ions involves the central metal atom forming six bonds with fluorine atoms.
This requires the central atom to have vacant d-orbitals to accommodate the lone pairs from the fluorine atoms.
Let's analyze each option:
ā¢ Option 1: Boron (B)
- Boron belongs to Group 13 and has the electronic configuration
1s22s22p1. - Boron does not have vacant d-orbitals in its valence shell (n=2) to expand its coordination number to 6.
- Therefore, boron cannot form
BF63āā. ā¢ Option 2: Aluminum (Al)
- Aluminum has the electronic configuration
[Ne]3s23p1. - Aluminum can utilize its 3d orbitals to expand its coordination number, allowing it to form
AlF63āā. ā¢ Option 3: Gallium (Ga)
- Gallium has the electronic configuration
[Ar]3d104s24p1. - Gallium can use its 4d orbitals to form
GaF63āā. ā¢ Option 4: Indium (In)
- Indium has the electronic configuration
[Kr]4d105s25p1. - Indium can utilize its 5d orbitals to form
InF63āā. Therefore, the element that is unable to form
MF63āā is Boron (B).
This corresponds to Option 1.