Kelvi

Calculate the energy corresponding to light of wavelength $45$ nm (Planck’s constant $h = 6.63 \times 10^{-34}$ Js: speed of light $c = 3 \times 10^8$ ms $^{-1})$

medium

Structure of Atom

2014

chemistry

$6.67 × 10^{15} J$

$6.67 × 10^{11} J$

$4.42 × 10^{-15} J$

Explanation

To calculate the energy corresponding to light of wavelength $45$ nm, we use the formula for energy of a photon: $\\ E = \frac{hc}{\lambda} \\$ Where: $\\$ •

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Calculate the energy corresponding to light of wavelength 45 45 45 nm (Planck’s constant h=6.63×10−34 h = 6.63 \times 10^{-34} h=6.63×10−34 Js: speed of light c=3×108 c = 3 \times 10^8 c=3×108 ms−1)^{-1})−1)

Explanation

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Calculate the energy corresponding to light of wavelength $45$ nm (Planck’s constant $h = 6.63 \times 10^{-34}$ Js: speed of light $c = 3 \times 10^8$ ms $^{-1})$