Kelvi

A thin semicircular conducting ring (PQR) of radius $r$ is falling with its plane vertical in a horizontal magnetic field $B.$ The potential difference developed across the ring when its speed is $v,$ is

medium

Electromagnetic Induction

2014

physics

$\frac{B v \pi r^2}{2},$ and P is at higher potential

$\frac{B v \pi r}{2},$

Explanation

To solve this problem, we need to determine the potential difference across the semicircular ring. $\\$ Given: $\\$ • Radius of the semicircular ring $r. \\$ • Magnetic field $B$ is horizontal. $\\$ • Speed of the ring $v. \\$

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A thin semicircular conducting ring (PQR) of radius r r r is falling with its plane vertical in a horizontal magnetic field B. B. B. The potential difference developed across the ring when its speed is v, v, v, is

Explanation

Our AI powered practice platform can help you achieve your doctor dream.

A thin semicircular conducting ring (PQR) of radius $r$ is falling with its plane vertical in a horizontal magnetic field $B.$ The potential difference developed across the ring when its speed is $v,$ is