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Red blood cells have no nucleus, making more room to carry oxygen-binding haemoglobin.
Which amongst the following is an incorrect statement?
medium
Chemical bonding and Molecular structure
2022
chemistry
The bond orders of O2+ā,O2ā,O2āā and O22āā are 2.5, 2, 1.5 and 1, respectively.
C2ā molecule has four electrons in its two degenerate Ļ molecular orbitals.
H2+ā ion has one electron.
O2+ā ion is diamagnetic.
Explanation
To determine the incorrect statement, we will analyze each option step-by-step.Option 1:The bond orders of O2+ā,O2ā,O2āā
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O22āā are 2.5, 2, 1.5 and 1, respectively.
ā¢ Bond order is calculated using the formula:
Bond order
=21ā( Number of bonding electrons
Number of antibonding electrons
ā¢ For
Electronic configuration:
(Ļ1sā)2(Ļ1sāā)2(Ļ2sā)2(Ļ2sāā)2(Ļ2pzāā)2(Ļ2pxāā)2(Ļ2pyāā)2(Ļ2pxāāā)1(Ļ2pyāāā)1 ā¢ Bond order for
O2ā=21ā(10ā6)=2 ā¢ For
Remove one electron from
Ļ2pxāāā or
Ļ2pyāāā orbital.
Bond order for
O2+ā=21ā(10ā5)=2.5 ā¢ For
O2āā: Add one electron to
Ļ2pxāāā or
Ļ2pyāāā orbital.
Bond order for
O2āā=21ā(10ā7)=1.5 ā¢ For
O22āā: Add two electrons to
Ļ2pxāāā and
Ļ2pyāāā orbitals.
Bond order for
O22āā=21ā(10ā8)=1 Thus, Option 1 is correct.
Option 2:
C
molecule has four electrons in its two degenerate
molecular orbitals.
ā¢ The electronic configuration of
is
(Ļ1sā)2(Ļ1sāā)2(Ļ2sā)2(Ļ2sāā)2(Ļ2pxāā)2(Ļ2pyāā)2 ā¢ The
Ļ2pxāā and
Ļ2pyāā orbitals are degenerate and each contains 2 electrons.
Thus, Option 2 is correct.
Option 3:
H
ion has one electron.
ā¢
is formed by removing one electron from
leaving it with one electron.
Thus, Option 3 is correct.
Option 4:
ion is diamagnetic.
ā¢
has an unpaired electron in the
Ļ2pxāāā or
Ļ2pyāāā orbital, making it paramagnetic.
Thus, Option 4 is incorrect.
Therefore, the incorrect statement is Option 4.