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Match the Xenon compounds in Column-I with its structure in Column-II and assign the correct code:
| Column I | Column II |
|---|
(a)XeF4ā | (ii) Square planar |
(b)XeF6ā | (iii) Distorted octahedral |
(c)XeOF4ā | (iv) Square pyramidal |
(d)XeO3ā | (i) Pyramidal |
hard
Chemical bonding and Molecular structure
2019
chemistry
| (a)-(i) | (b)-(ii) | (c)-(iii) | (d)-(iv) | | (a)-(ii) | (b)-(iii) | (c)-(iv) | (d)-(i) | | (a)-(ii) | (b)-(iii) | (c)-(i) | (d)-(iv) | | (a)-(iii) | (b)-(iv) | (c)-(i) | (d)-(ii) | Explanation
To solve this problem, we need to match each Xenon compound with its corresponding structure. Let's analyze each compound:ā¢ XeF4ā:XeF4ā
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Sign up / Login has a central xenon atom surrounded by four fluorine atoms. The structure is
square planar
This is because Xe has 8 valence electrons, 4 are used for bonding with F, and 2 lone pairs remain, resulting in a
square planar
geometry.
ā¢
XeF
XeF
has a central xenon atom surrounded by six fluorine atoms. The structure is
distorted octahedral
Xe has 8 valence electrons, 6 are used for bonding with F, and 1 lone pair remains, causing distortion in the octahedral geometry.
ā¢
XeOF
XeOF
has a central xenon atom bonded to one oxygen and four fluorine atoms. The structure is
square pyramidal
Xe has 8 valence electrons, 5 are used for bonding (4 with F and 1 with O), and 1 lone pair remains, resulting in a
square pyramidal
geometry.
ā¢
XeO
XeO
has a central xenon atom bonded to three oxygen atoms. The structure is
pyramidal
Xe has 8 valence electrons, 6 are used for bonding with O, and 1 lone pair remains, resulting in a
pyramidal
geometry.
Based on this analysis, the correct matching is:
(a)ā(ii),(b)ā(iii),(c)ā(iv),(d)ā(i). Therefore, the correct option is Option 2.