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The correct option for the value of vapor pressure of a solution at $45^\circ C$ with benzene to octane in molar ratio $3:2$ is: $\newline$ (At $45^\circ C,$ vapor pressure of benzene is $280$ mm Hg and that of octane is $420$ mm Hg. Assume Ideal gas)

medium

Solutions

2021

chemistry

$160$ mm of Hg

$168$ mm of Hg

$336$ mm of Hg

$350$ mm of Hg

Explanation

To solve this problem, we will use Raoult's Law for ideal solutions. $\\$ Raoult's Law states that the vapor pressure of a solution $(P_{solution}) \\$ is given by the sum of the partial pressures of each component. $\\$ The partial pressure of each component is the product of its mole fraction $(X) \\$

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The correct option for the value of vapor pressure of a solution at 45∘C 45^\circ C 45∘C with benzene to octane in molar ratio 3:2 3:2 3:2 is: \newline (At 45∘C, 45^\circ C, 45∘C, vapor pressure of benzene is 280 280 280 mm Hg and that of octane is 420 420 420 mm Hg. Assume Ideal gas)

Explanation

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The correct option for the value of vapor pressure of a solution at $45^\circ C$ with benzene to octane in molar ratio $3:2$ is: $\newline$ (At $45^\circ C,$ vapor pressure of benzene is $280$ mm Hg and that of octane is $420$ mm Hg. Assume Ideal gas)