Kelvi

The displacement of a particle executing simple harmonic motion is given by $y = A_0 + A \sin \omega t + B \cos \omega t.$ Then the amplitude of its oscillation is given by:

easy

Oscillations

2019

physics

$A_0 + \sqrt{A^2 + B^2}$

Explanation

To find the amplitude of the oscillation for a particle executing simple harmonic motion, we start with the given displacement equation: $\\ y = A_0 + A \sin \omega t + B \cos \omega t \\$ In simple harmonic motion, the displacement can be expressed as: $\\ y = C \sin(\omega t + \phi) \\$

Our AI powered practice platform can help you achieve your doctor dream.

Practice 2000+ previous year NEET questions
More practice, more score
AI generated hints
Use hints to get start solving
AI companion chat to clear doubts 24*7
Ask any question, get instant answers
AI generated solutions
Get detailed step by step solutions
Check related NCERT content
Read while solving
Track your progress
Improve every day

The displacement of a particle executing simple harmonic motion is given by y=A0+Asin⁡ωt+Bcos⁡ωt. y = A_0 + A \sin \omega t + B \cos \omega t. y=A0​+Asinωt+Bcosωt. Then the amplitude of its oscillation is given by:

Explanation

Our AI powered practice platform can help you achieve your doctor dream.

The displacement of a particle executing simple harmonic motion is given by $y = A_0 + A \sin \omega t + B \cos \omega t.$ Then the amplitude of its oscillation is given by: