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A long solenoid of $50$ cm length having $100$ turns carries a current of $2.5$ A. The magnetic field at the centre of the solenoid is: $\newline (\mu_0 = 4\pi \times 10^{-7}$ T m A $^{-1})$

easy

Moving Charges and Magnetism

2020

physics

$3.14 \times 10^{-4}$ T

$6.28 \times 10^{-5}$ T

$3.14 \times 10^{-5}$

Explanation

To solve this problem, we will use the formula for the magnetic field inside a solenoid. $\\$ The magnetic field $B$ inside a long solenoid is given by: $\\ B = \mu_0 \cdot n \cdot I \\$

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A long solenoid of 50 50 50 cm length having 100 100 100 turns carries a current of 2.5 2.5 2.5 A. The magnetic field at the centre of the solenoid is:(μ0=4π×10−7 \newline (\mu_0 = 4\pi \times 10^{-7} (μ0​=4π×10−7 T m A−1)^{-1})−1)

Explanation

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A long solenoid of $50$ cm length having $100$ turns carries a current of $2.5$ A. The magnetic field at the centre of the solenoid is: $\newline (\mu_0 = 4\pi \times 10^{-7}$ T m A $^{-1})$