To solve this problem, we need to calculate the frequency of allele A in the population. Let's analyze the given data:$\newline \bullet$The population consists of 1000 individuals, with the following genotypes:$\newline$ - 360 individuals with genotype AA$\newline$ - 480 individuals with genotype Aa$\newline$ - 160 individuals with genotype aa$\newline$To find the frequency of allele A, we use the formula:$\newline$Frequency of allele A$= \frac{Number \ of \ A \ alleles}{Total \ number \ of \ alleles}\newline \bullet$Calculate the number of A alleles:$\newline$ - Each AA individual contributes 2 A alleles, so $360 \times 2 = 720$ A alleles from AA individuals.$\newline$ - Each Aa individual contributes 1 A allele, so $480 \times 1 = 480$ A alleles from Aa individuals.$\newline$ - Total number of A alleles = 720 + 480 = 1200.$\newline \bullet$Calculate the total number of alleles in the population:$\newline$ - Each individual has 2 alleles, so $1000 \times 2 = 2000$ total alleles.$\newline \bullet$Calculate the frequency of allele A:$\newline$Frequency of allele A$= \frac{1200}{2000} = 0.6 \newline$Therefore, the frequency of allele A in the population is 0.6.$\newline$This corresponds to Option 3.