Kelvi

A block of mass $m$ is placed on a smooth inclined wedge ABC of inclination $\theta$ as shown in the figure. The wedge is given an acceleration $a$ towards the right. The relation between $a$ and $\theta$ for the block to remain stationary on the wedge is

medium

Laws of Motion

2018

physics

$a = g \cos \theta$

$a = \frac{g}{\sin \theta}$

Explanation

To solve this problem, we need to analyze the forces acting on the block. $\\$ Consider the block of mass $m$ on the inclined plane with inclination $\theta. \\$ The wedge is accelerating to the right with acceleration $a. \\$ For the block to remain stationary relative to the wedge, the net force parallel to the incline must be zero. $\\$ Let's analyze the forces: $\\$

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A block of mass m m m is placed on a smooth inclined wedge ABC of inclination θ \theta θ as shown in the figure. The wedge is given an acceleration a a a towards the right. The relation between a a a and θ \theta θ for the block to remain stationary on the wedge is

Explanation

Our AI powered practice platform can help you achieve your doctor dream.

A block of mass $m$ is placed on a smooth inclined wedge ABC of inclination $\theta$ as shown in the figure. The wedge is given an acceleration $a$ towards the right. The relation between $a$ and $\theta$ for the block to remain stationary on the wedge is