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A $10 \mu F$ capacitor is connected to a $210 V, 50 Hz$ source as shown in figure. The peak current in the circuit is nearly ( $\pi = 3.14$ ):

medium

Alternating Current

2024

physics

1.20 A

0.35 A

0.58 A

0.93 A

Explanation

To find the peak current in the circuit, we need to calculate the capacitive reactance and then use it to find the current. $\\$ Given: $\\$ • Capacitance $C = 10 \mu F = 10 \times 10^{-6} F \\$

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A 10μF 10 \mu F 10μF capacitor is connected to a 210V,50Hz 210 V, 50 Hz 210V,50Hz source as shown in figure. The peak current in the circuit is nearly ( π=3.14 \pi = 3.14 π=3.14):

Explanation

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A $10 \mu F$ capacitor is connected to a $210 V, 50 Hz$ source as shown in figure. The peak current in the circuit is nearly ( $\pi = 3.14$ ):