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The reaction of C $_6$ H $_5$ CH $=$ CHCH $_3$ with HBr produces

medium

Hydrocarbons

2015

chemistry

option

option

option

option

Explanation

To solve this problem, we need to understand the reaction of an alkene with HBr. $\\$ The given compound is $C_6H_5CH=CHCH_3. \\$

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This is an example of an electrophilic addition reaction, following Markovnikov's rule.

\\

Markovnikov's rule states that the hydrogen atom from HBr will add to the carbon with more hydrogen atoms,

\\

and the bromine atom will add to the carbon with fewer hydrogen atoms.

\\

Step-by-step reaction:

\\

1. The double bond between

CH=CH

is the site of reaction.

\\

2. The

CH_3

group is attached to the second carbon of the double bond.

\\

3. According to Markovnikov's rule, the H from HBr will add to the

CH

group,

\\

and Br will add to the

CH_2

group.

\\

4. The resulting product is

C_6H_5CHBrCH_2CH_3. \\

This corresponds to Option 4.

\\

Therefore, the correct product of the reaction is

C_6H_5CHBrCH_2CH_3.