Kelvi

Two particles of masses $m_1, m_2$ move with initial velocities $u_1$ and $u_2.$ On collision, one of the particles gets excited to a higher level, after absorbing energy $\varepsilon.$ If final velocities of the particles be $v_1$ and $v_2$ then we must have:

medium

Work, Energy and Power

2015

physics

$\frac{1}{2} m_1 u_1^2 + \frac{1}{2} m_2 u_2^2 = \frac{1}{2} m_1 v_1^2 + \frac{1}{2} m_2 v_2^2 - \varepsilon$

Explanation

To solve this problem, we need to apply the principle of conservation of energy. $\\$ The initial kinetic energy of the system is given by: $\\ \frac{1}{2} m_1 u_1^2 + \frac{1}{2} m_2 u_2^2 \\$

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