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A tightly wound 100 turns coil of radius 10 cm carries a current of 7A. The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as $4\pi \times 10^{-7}$ SI units):

easy

Magnetism and Matter

2024

physics

$4.4$ mT

44T

$44$ mT

4.4T

Explanation

To solve this problem, we will use the formula for the magnetic field at the center of a circular coil. $\\$ The formula for the magnetic field $B$ at the center of a circular coil is given by: $\\ B = \frac{\mu_0 \cdot N \cdot I}{2R} \\$

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A tightly wound 100 turns coil of radius 10 cm carries a current of 7A. The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as 4π×10−7 4\pi \times 10^{-7} 4π×10−7 SI units):

Explanation

Our AI powered practice platform can help you achieve your doctor dream.

A tightly wound 100 turns coil of radius 10 cm carries a current of 7A. The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as $4\pi \times 10^{-7}$ SI units):