Kelvi

The refracting angle of a prism is $A,$ and the refractive index of the material of the prism is $\cot(A/2).$ The angle of minimum deviation is

hard

Ray Optics and Optical Instruments

2015

physics

$180^{\circ} - 2A$

$90^{\circ} - A$

$180^{\circ} + 2A$

$180^{\circ} - 3A$

Explanation

To solve this problem, we need to use the formula for the angle of minimum deviation in a prism. $\\$ Given: $\\$ • The refracting angle of the prism is $A. \\$ • The refractive index of the material of the prism is $\mu = \cot\left(\frac{A}{2}\right). \\$

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The refracting angle of a prism is A, A, A, and the refractive index of the material of the prism is cot⁡(A/2). \cot(A/2). cot(A/2). The angle of minimum deviation is

Explanation

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The refracting angle of a prism is $A,$ and the refractive index of the material of the prism is $\cot(A/2).$ The angle of minimum deviation is