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A thin spherical shell is charged by some source. The potential difference between the two points C and P (in V) shown in the figure is: $\\ ( \frac{1}{4\pi \varepsilon_0} = 9 \times 10^9$ SI units $)$

easy

Electrostatic Potential and Capacitance

2024

physics

$0.5 \times 10^5$

Zero

$3 \times 10^5$

$1 \times 10^5$

Explanation

To solve this problem, we need to understand the potential difference between two points on a charged spherical shell. $\\$ Given: $\\$ • Charge on the shell $q = 1 \mu C = 1 \times 10^{-6} C \\$

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A thin spherical shell is charged by some source. The potential difference between the two points C and P (in V) shown in the figure is:(14πε0=9×109 \\ ( \frac{1}{4\pi \varepsilon_0} = 9 \times 10^9 (4πε0​1​=9×109 SI units)))

Explanation

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A thin spherical shell is charged by some source. The potential difference between the two points C and P (in V) shown in the figure is: $\\ ( \frac{1}{4\pi \varepsilon_0} = 9 \times 10^9$ SI units $)$