Kelvi

From a disc of radius $R$ and mass $M,$ a circular hole of diameter $R,$ whose rim passes through the centre, is cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis passing through the centre?

hard

System of Particles and Rotational Motion

2016

physics

$\frac{11}{32} MR^2$

$\frac{9}{32} MR^2$

$\frac{15}{32} MR^2$

$\frac{13}{32} MR^2$

Explanation

To solve this problem, we need to find the moment of inertia of the remaining part of the disc after a circular hole is cut out. $\\$ Given: $\\$ • Radius of the original disc $= R \\$ • Mass of the original disc $= M \\$ • Diameter of the hole $= R \\$

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From a disc of radius R R R and mass M, M, M, a circular hole of diameter R, R, R, whose rim passes through the centre, is cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis passing through the centre?

Explanation

Our AI powered practice platform can help you achieve your doctor dream.

From a disc of radius $R$ and mass $M,$ a circular hole of diameter $R,$ whose rim passes through the centre, is cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis passing through the centre?