To determine the IUPAC name of the given compound, follow these steps:$\newline$1. Identify the functional groups:$\newline$• The compound contains an aldehyde group (CHO) and a ketone group (C=O).$\newline$2. Determine the longest carbon chain containing the highest priority functional group:$\newline$• The longest chain with the aldehyde group has 6 carbon atoms, making it a hexanal derivative.$\newline$3. Number the carbon chain:$\newline$• Start numbering from the aldehyde group, as it has the highest priority.$\newline$• The aldehyde group is at position 1, and the ketone group is at position 3.$\newline$4. Identify any double bonds:$\newline$• There is a double bond between carbons 4 and 5.$\newline$5. Identify any substituents:$\newline$• There is a methyl group at position 2.$\newline$6. Assemble the IUPAC name:$\newline$• The compound is named as a hexanal derivative with a ketone at position 3, a methyl group at position 2,$\newline$ and a double bond starting at position 4.$\newline$• The correct IUPAC name is 3-keto-2-methylhex-4-enal.$\newline$Therefore, the correct option is Option 4.