Kelvi

A thermodynamic system undergoes cyclic process ABCDA as shown in the figure. The work done by the system in the cycle is

medium

Thermodynamics

2014

physics

$P_0 V_0$

$2P_0 V_0$

$\frac{P_0 V_0}{2}$

Explanation

To solve this problem, we need to calculate the work done by the system in the cyclic process ABCDA. $\\$ The work done in a cyclic process is equal to the area enclosed by the cycle on the PV diagram. $\\$ Let's analyze the given PV diagram: $\\$ • The cycle is a rectangle with vertices A, B, C, and D. $\\$ • The coordinates of these points are: $\\$ A: $(V_0, P_0) \\$

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