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A wire of length $L,$ area of cross-section $A,$ is hanging from a fixed support. The length of the wire changes to $L_1$ when mass $M$ is suspended from its free end. The expression for Young’s modulus is:

medium

Mechanical Properties of Solids

2020

physics

$\frac{Mg(L_1 - L)}{AL}$

$\frac{MgL}{AL_1}$

Explanation

To solve this problem, we need to find the expression for Young's modulus of the wire. $\\$ Young's modulus $(Y)$ is defined as the ratio of tensile stress to tensile strain. $\\$ Tensile stress is given by: $\\ \frac{Force}{Area} = \frac{Mg}{A} \\$

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A wire of length L, L, L, area of cross-section A, A, A, is hanging from a fixed support. The length of the wire changes to L1 L_1 L1​ when mass M M M is suspended from its free end. The expression for Young’s modulus is:

Explanation

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A wire of length $L,$ area of cross-section $A,$ is hanging from a fixed support. The length of the wire changes to $L_1$ when mass $M$ is suspended from its free end. The expression for Young’s modulus is: