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Diamonds and graphite are both made of pure carbon — just arranged differently.
The product formed in the following chemical reaction is: hard
Aldehydes, Ketones and Carboxylic Acids
2021
chemistry
Explanation To solve this problem, we need to understand the reaction taking place. \\
The given reaction involves the reduction of a compound using N a B H 4 \mathrm{NaBH_4} NaB H 4 in C 2 H 5 O H . \mathrm{C_2H_5OH}. \\
C 2 H 5 OH .
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Let's analyze the structure of the reactant:
• The reactant has two carbonyl groups: a ketone and an ester.
Sodium borohydride (NaBH
) is a selective reducing agent that typically reduces aldehydes and ketones,
but not esters under normal conditions.
Therefore, in this reaction, only the ketone group will be reduced to an alcohol.
Let's identify the product:
• The ketone group in the cyclohexane ring will be reduced to a secondary alcohol.
• The ester group will remain unchanged.
Now, let's compare with the options:
Option 1: Both the ketone and ester are reduced, which is incorrect.
Option 2: The ester is reduced, which is incorrect.
Option 3: Both the ketone and ester are reduced, which is incorrect.
Option 4: Only the ketone is reduced, which is correct.
Therefore, the correct product is shown in Option 4.
