To solve this problem, we need to determine the cause of an abnormal human baby with 'XXX' sex chromosomes.$\newline$Let's analyze each option:$\newline \bullet$Option 1: Formation of abnormal sperms in the father.$\newline$ - Typically, male gametes (sperms) carry either an X or a Y chromosome.$\newline$ - Abnormal sperms could potentially carry an extra chromosome, but this would not result in an 'XXX' condition.$\newline$ - Therefore, this option is unlikely to be the cause.$\newline \bullet$Option 2: Formation of abnormal ova in the mother.$\newline$ - Female gametes (ova) normally carry one X chromosome.$\newline$ - An abnormal ovum could carry two X chromosomes due to nondisjunction during meiosis.$\newline$ - If such an ovum is fertilized by a normal X-carrying sperm, the result would be an 'XXX' condition.$\newline$ - Therefore, this option is a plausible cause.$\newline \bullet$Option 3: Fusion of two ova and one sperm.$\newline$ - This scenario is biologically implausible as it would not result in a viable zygote.$\newline$ - Therefore, this option is not a valid cause.$\newline \bullet$Option 4: Fusion of two sperms and one ovum.$\newline$ - This scenario, known as polyspermy, typically results in an inviable zygote.$\newline$ - Therefore, this option is not a valid cause.$\newline$Based on the analysis, the most likely cause of an 'XXX' sex chromosome condition is:$\newline$Option 2: Formation of abnormal ova in the mother.$\newline$This corresponds to the correct option, which is Option 2.