Kelvi

A shell of mass $m$ is at rest initially. It explodes into three fragments having mass in the ratio $2 : 2: 1.$ If the fragments having equal mass fly off along mutually perpendicular directions with speed $v,$ the speed of the third (lighter) fragment is:

medium

System of Particles and Rotational Motion

2022

physics

$\sqrt{2}v$

$2\sqrt{2} v$

Explanation

To solve this problem, we will use the principle of conservation of momentum. $\\$ Given: $\\$ • The shell is initially at rest, so its initial momentum is zero. $\\$ • The shell explodes into three fragments with mass ratio $2:2:1. \\$ Let's denote: $\\$ • Total mass of the shell as

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A shell of mass m m m is at rest initially. It explodes into three fragments having mass in the ratio 2:2:1. 2 : 2: 1. 2:2:1. If the fragments having equal mass fly off along mutually perpendicular directions with speed v, v, v, the speed of the third (lighter) fragment is:

Explanation

Our AI powered practice platform can help you achieve your doctor dream.

A shell of mass $m$ is at rest initially. It explodes into three fragments having mass in the ratio $2 : 2: 1.$ If the fragments having equal mass fly off along mutually perpendicular directions with speed $v,$ the speed of the third (lighter) fragment is: