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Iron exhibits bcc structure at room temperature. Above $900^\circ$ C $,$ it transforms to fcc structure. The ratio of density of iron at room temperature to that at $900^\circ$ C (assuming molar mass and atomic radii of iron remains constant with temperature) is

hard

Coordination Compounds

2018

chemistry

$\frac{3 \sqrt{3}}{4 \sqrt{2}}$

Explanation

To solve this problem, we need to find the ratio of the density of iron in bcc structure to that in fcc structure. $\\$ The density $\rho$ of a crystal is given by: $\\ \rho = \frac{Z \cdot M}{a^3 \cdot N_A} \\$

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Iron exhibits bcc structure at room temperature. Above 900∘ 900^\circ900∘C,, , it transforms to fcc structure. The ratio of density of iron at room temperature to that at 900∘ 900^\circ900∘C (assuming molar mass and atomic radii of iron remains constant with temperature) is

Explanation

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Iron exhibits bcc structure at room temperature. Above $900^\circ$ C $,$ it transforms to fcc structure. The ratio of density of iron at room temperature to that at $900^\circ$ C (assuming molar mass and atomic radii of iron remains constant with temperature) is