Kelvi

A capacitor of capacitance $C = 900 pF$ is charged fully by a $100V$ battery. Then the battery is disconnected, and the capacitor is connected to another uncharged capacitor of capacitance $C = 900 pF.$ The electrostatic energy stored by the system is:

medium

Electrostatic Potential and Capacitance

2022

physics

$4.5 \times 10^{-6} J$

$3.25 \times 10^{-6} J$

Explanation

To solve this problem, we need to calculate the electrostatic energy stored in the system after the capacitors are connected. $\\$ Given: $\\$ • Initial capacitance $C_1 = 900 \,$ pF $= 900 \times 10^{-12} \,$

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A capacitor of capacitance C=900pF C = 900 pF C=900pF is charged fully by a 100V 100V 100V battery. Then the battery is disconnected, and the capacitor is connected to another uncharged capacitor of capacitance C=900pF. C = 900 pF. C=900pF. The electrostatic energy stored by the system is:

Explanation

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A capacitor of capacitance $C = 900 pF$ is charged fully by a $100V$ battery. Then the battery is disconnected, and the capacitor is connected to another uncharged capacitor of capacitance $C = 900 pF.$ The electrostatic energy stored by the system is: