To solve this problem, we need to identify the compound with the molecular formula $\mathrm{C_6H_{14}}$ that has two tertiary carbons.$\\$A tertiary carbon is a carbon atom bonded to three other carbon atoms.$\\$Let's analyze the options:$\\$Option 1: $$2,3-Dimethylbutane$\\$• Structure: $$CH$_3-$C(CH$_3$)$_2-$CH$_2-$CH$_3 \\$• This compound has two tertiary carbons at positions 2 and 3.$\\$Option 2: $$2,2-Dimethylbutane$\\$• Structure: $$CH$_3-$C(CH$_3$)$_2-$CH$_2-$CH$_3 \\$• This compound has only one tertiary carbon at position 2.$\\$Option 3: $$n-Hexane$\\$• Structure: $$CH$_3-$CH$_2-$CH$_2-$CH$_2-$CH$_2-$CH$_3 \\$• This compound has no tertiary carbons.$\\$Option 4: $$2-Methylpentane$\\$• Structure: $$CH$_3-$CH(CH$_3$)$-$CH$_2-$CH$_2-$CH$_3 \\$• This compound has only one tertiary carbon at position 2.$\\$Therefore, the compound with two tertiary carbons is 2,3-Dimethylbutane.$\\$The correct IUPAC name is Option 1: 2,3-Dimethylbutane.