To solve this problem, we need to analyze each reaction:$\\$(a) $$CH$_3$CH$_2$CH$_2$Br$+$KOH$\rightarrow$CH$_3$CH$=$CH$_2 +$KBr$+$H$_2$O$\\$• This is an elimination reaction. The bromine (Br) and a hydrogen (H) are removed, forming an alkene.$\\$(b) $$H$_3$C$-$CHBr$-$CH$_3 +$KOH$\rightarrow$H$_3$C$-$CHOH$-$CH$_3 +$KBr$\\$• This is a substitution reaction. The bromine (Br) is replaced by a hydroxyl group (OH).$\\$(c) $$Cyclohexene$+$Br$_2 \rightarrow$1,2-Dibromocyclohexane$\\$• This is an addition reaction. The bromine (Br$_2$) adds across the double bond.$\\$Based on the analysis:$\\$• (a) is an elimination reaction.$\\$• (b) is a substitution reaction.$\\$• (c) is an addition reaction.$\\$Therefore, the correct statement is:$\\$Option 2: (a) is elimination, (b) is substitution and (c) is addition reaction.