Kelvi

A ball is thrown vertically downward with a velocity of $20$ m/s from the top of a tower. It hits the ground after some time with a velocity of $80$ m/s. The height of the tower is $(g = 10$ m/s $^2):$

medium

Motion in a Straight Line

2020

physics

$340$ m

$320$ m

$300$ m

$360$ m

Explanation

To solve this problem, we will use the kinematic equations for uniformly accelerated motion. $\\$ Given: $\\$ • Initial velocity $u = 20$ m/s (downward) $\\$ • Final velocity $v = 80$ m/s (downward) $\\$

Our AI powered practice platform can help you achieve your doctor dream.

Practice 2000+ previous year NEET questions
More practice, more score
AI generated hints
Use hints to get start solving
AI companion chat to clear doubts 24*7
Ask any question, get instant answers
AI generated solutions
Get detailed step by step solutions
Check related NCERT content
Read while solving
Track your progress
Improve every day

A ball is thrown vertically downward with a velocity of 20 20 20 m/s from the top of a tower. It hits the ground after some time with a velocity of 80 80 80 m/s. The height of the tower is (g=10 (g = 10 (g=10 m/s2):^2):2):

Explanation

Our AI powered practice platform can help you achieve your doctor dream.

A ball is thrown vertically downward with a velocity of $20$ m/s from the top of a tower. It hits the ground after some time with a velocity of $80$ m/s. The height of the tower is $(g = 10$ m/s $^2):$