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The graph which shows the variation of $\frac{1}{\lambda^2}$ and its kinetic energy, $E$ (where $\lambda$ is de Broglie wavelength of a free particle) :

medium

Dual Nature of Radiation and Matter

2024

physics

Explanation

To solve this problem, we need to understand the relationship between the de Broglie wavelength $\lambda$ and kinetic energy $E. \\$ The de Broglie wavelength is given by: $\\ \lambda = \frac{h}{p} \\$

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The graph which shows the variation of 1λ2 \frac{1}{\lambda^2} λ21​ and its kinetic energy, E E E (where λ \lambda λ is de Broglie wavelength of a free particle) :

Explanation

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The graph which shows the variation of $\frac{1}{\lambda^2}$ and its kinetic energy, $E$ (where $\lambda$ is de Broglie wavelength of a free particle) :