Kelvi

The approximate depth of an ocean is $2700$ m $.$ The compressibility of water is $45.4 \times 10^{-11}$ Pa $^{-1}$ and density of water is $10^3$ kg m $^{-3}.$ What fractional compression of water will be obtained at the bottom of the ocean?

medium

Mechanical Properties of Solids

2015

physics

$1.0 \times 10^{-2}$

$1.2 \times 10^{-2}$

$1.4 \times 10^{-2}$

Explanation

To solve this problem, we need to determine the fractional compression of water at the bottom of the ocean. $\\$ The formula for fractional compression is given by: $\\ \Delta V/V = -\beta \Delta P \\$ where: $\\$ • $\Delta V/V$

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The approximate depth of an ocean is 2700 2700 2700 m.. . The compressibility of water is 45.4×10−11 45.4 \times 10^{-11} 45.4×10−11 Pa−1^{-1} −1 and density of water is 103 10^3 103 kg m−3.^{-3}. −3. What fractional compression of water will be obtained at the bottom of the ocean?

Explanation

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The approximate depth of an ocean is $2700$ m $.$ The compressibility of water is $45.4 \times 10^{-11}$ Pa $^{-1}$ and density of water is $10^3$ kg m $^{-3}.$ What fractional compression of water will be obtained at the bottom of the ocean?